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The displacement of a particle is given by `y = a + bt + ct^2 - dt^4`. The initial velocity and acceleration are respectively.A. `b, -4d`B. `-b, 2c`C. `b,2c`D. `2c, -4d`

Answer» Correct Answer - C
`y = a + bt + ct^2 - dt^4`
`:. v = (dy)/(dt) = b+ 2ct - 4dt^3`
and `a = (dv)/(dt) = 2c - 12 dt^2`.
Hence, at `t = 0, v_("initial") = b and a_("initial") = 2 c`.


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