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The distance between the point (3-2) and (-3,2) |
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Answer» X1= 3 ,X2=( -2) ,y1= (-3) ,y2=2 Distance formula X=√(x2-x1)+(y2+y1) =√ (-2-3)2+{2-(-3)}2=√(-5)2+(2+3)2=√(-5)2+(5)2=√25+25=√50 Sorry by mistake value write wrong ....x1 & x2= 3,-3 and y 1&y2= -2,2 Distance formula = underroot ( x2-x1)+(y2-y1)Here x1=3,x2=-2 and y1=-3 and y2=2 |
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