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| 1. |
The distance between the points (2,-2)&(-1,x) is 5 then one of the value of x is\xa0 |
| Answer» Given : A (2,-2) and B(-1,x) and Distance b/w these two is 5according to distance formula(x2-x1)2 + (y2-y1)2 = d2=> (-1-2)2 + (x+2)2 = 25=> 9 + x2 + 4 +4x = 25=> x2 + 4x - 12 = 0=> x2 + 6x -2x - 12 = 0=> x (x+6) -2(x+6) = 0\xa0=> (x+6) (x-2) = 0either x + 6 = 0 or x-2=0so x = -6, 2\xa0 | |