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The factorisation of 3x²-15x+28 |
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Answer» L.C.M. of 3×28=74;3 742 282 14 7Therefore, 3x^2-15x+28 =>3x^2-12x-7x+28 =>3x(x-4)-7(x-4) =>(x-4)(3x-7)Then, (x-4)=0 and (3x-7)=0Theefore, x=4 and x=7/3Now,4 and 7/3 are the roots of the given equation 3x^2-15x+28 If we find discriminant it will be( -111) which means that it does not have real roots No real roots |
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