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| 1. |
The first term of ap are 3y-1,3y+5 and 5y+1 respectively. |
| Answer» {tex}3y - 1,3y + 5{/tex} and {tex}5y + 1{/tex} in A.P.{tex}(3y + 5 ) - ( 3 y - 1) = (5y + 1) - (3y + 5){/tex}or, {tex}3y + 5 - 3y + 1 = 5y + 1 - 3y - 5{/tex}or, {tex}6 = 2y - 4{/tex}or, {tex}2y = 6 + 4{/tex}or, {tex}2y = 10{/tex}or, y =\xa0{tex}\\frac{10}{2}{/tex}{tex}y = 5{/tex} | |