The first three tremendous an AP 3y-1,3y±5& 5y±1 then find the value

1.	The first three tremendous an AP 3y-1,3y±5& 5y±1 then find the value of yuan.
Answer» Since {tex}(3y-1), (3y+5)\\ and\\ (5y+1){/tex} are in AP, we have{tex}(3y+5)-(3y-1)=(5y+1)-(3y+5){/tex}{tex} \\Rightarrow {/tex}\xa0{tex}3y+5-3y+1=5y+1-3y-5{/tex}{tex} \\Rightarrow {/tex}\xa0{tex}6=2y-4{/tex}{tex} \\Rightarrow {/tex}\xa02y=10{tex} \\Rightarrow {/tex}\xa0y=5

Discussion