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The function `f(x) =cot x` is discontinuous on setA. `{x=npi:ninZ }`B. `{x = 2npi : n in Z }`C. ` {x =(2n+1)(pi)/(2),n in Z}`D. `{x=(npi)/(2), n in Z}` |
Answer» Correct Answer - A We know that, `f(x) = cotx` is continuous in `R-{npi:ninZ}`. Since, `f(x) = cotx = (cosx)/(sinx)`, [since, `sinx = 0` at `n pi, n in Z`] Hence`f(x)= cotx` is discontinuous on the set ` {x=npi : n in Z}`. |
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