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The greatest number which on dividing 1659 and 2036 leaves remainders 8 and 4 respectively |
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Answer» 127 Since,Remainders are 8 and 4In the given question,Greatest required number = H.C.F of (1659 - 8) and (2037 - 5) = H.C.F of 1651 and 2032 = 127 Remainders are 8 and 4 1659-8=16512036-4=2032HCF of 1651 and 2032 is 127=>the greatest no. is 127 |
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