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The half-life of `._(6)C^(14)`, if its decay constant is `6.31 xx 10^(-4)` isA. 1098 yrB. `109.8 yr`C. `10.98 yr`D. `1.098 yr` |
Answer» Correct Answer - A `t_(1//2) = (0.693)/(k) = (0.693)/(6.31 xx 10^(-4)) = 0.1098 xx 10^(4) = 1098 yr` |
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