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| 1. |
The hcf of 96 and 408 by prime factorisation method and hence find their lcm. |
| Answer» We have,{tex}96 = 2 ^ { 5 } \\times 3{/tex} and {tex}404 = 2 ^ { 2 } \\times 101{/tex}{tex}\\therefore \\quad \\mathrm { HCF } = 2 ^ { 2 } = 4{/tex}Now, {tex}\\mathrm { HCF } \\times \\mathrm { LCM } = 96 \\times 404{/tex}{tex}\\Rightarrow \\quad \\mathrm { LCM } = \\frac { 96 \\times 404 } { \\mathrm { HCF } } = \\frac { 96 \\times 404 } { 4 }{/tex}{tex}= 96 \\times 101 = 9696{/tex} | |