The HCF of two number is 23 and their LCM is 1449 . If one of the number is 161 , find the other

The HCF of two number is 23 and their LCM is 1449 . If one of the numb

1.	The HCF of two number is 23 and their LCM is 1449 . If one of the number is 161 , find the other
Answer» Let the two numbers be a and bHCF = 23LCM = 1449a = 161We have to find b.HCF(a,b)xLCM(a,b) = axb∴23x1449 = 161x b∴b = 207Thus, the other number is 207. let the numbers = 161 , aproduct of two nos = hcf x lcm161 x a = hcf x lcm\xa0 a = 23 x 1449 /161 = 1449/7 = 207