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| 1. |
The larger of two supplementary angles exceed the smaller by 18 degrees find them |
| Answer» Let the angle be x\xa0other angle (it\'s supplement) =( 180-x)x+18= (180-x)2x = 162x = 162/2 = 81\xa0other angle(its supplement) = 180- x => 180-81 => 99 | |