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The left hand derivative of `f(x)=[x]sin(pix)` at `x = k`, `k` is an integer, isA. `(-1)^(k) (k-1)pi`B. `(-1)^(k-1) (k-1)pi`C. `(-1)^(k)kpi`D. `(-1)^(k-1)kpi` |
Answer» Correct Answer - A We have `f(x)=[x] sin pi x` `therefore ("LHD at x=k")=underset(x to k^(-))lim (f(x)-f(k))/(x-k)` `Rightarrow ("LHD at x=k")=underset(h to 0)lim (f(k-h)-f(k))/(-h)` `Rightarrow ("LHD at x=k")=underset(h to 0)lim ([k-h)sin (pik-pih)-[k]sin pik)/(-h)` `Rightarrow ("LHD at x=k")=underset(h to 0)lim ((-1)^(k-1)[k-h]sin pi h-0)/(-h)` `Rightarrow ("LHD at x=k")=underset(h to 0)lim (-1)^(k) [k-h] (sin pi h)/(h)` `Rightarrow ("LHD at x=k")=(-1)^(k) (k-1) underset(h to 0)lim (sin pi h)/(h)=(-1)^(k) (k-1)pi` |
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