The mid point of the line segment joining (2a,4) and (-2,2b) is (1,2a+1).find the value of b?

The mid point of the line segment joining (2a,4) and (-2,2b) is (1,2a+

1.	The mid point of the line segment joining (2a,4) and (-2,2b) is (1,2a+1).find the value of b?
Answer» Midpoint of two given points are\xa0{(x1\xa0+ x2)/2, (y1\xa0+ y2)/2}According to question,(2a - 2)/2 = 12a - 2 = 22a = 4a = 2Again, (4 + 2b)/2 = 2a + 14 + 2b = 4a + 22b = 4 × 2 + 2 - 42b = 8 - 2b = 3 Mid point = (x1+x2)/2 ; (y1+y2)/21 = (2a+1)/22 = 2a+12a = 1a =1/22a+ 1 = (4+2b)/24a+2 = 4 +2b4a-2 = 2b2a-1 = b1 - 1 =bb=0