The no. Of real roots of the equation(X-1)*2+ (X-2)*2 +(x -3)*2=0 is.Please explain this.

The no. Of real roots of the equation(X-1)*2+ (X-2)*2 +(x -3)*2=0 is.P

1.	The no. Of real roots of the equation(X-1)2+ (X-2)2 +(x -3)*2=0 is.Please explain this.
Answer» One zeroBecause degree of polynomial is 1 Answer is x=22x-2+2x-4+2x-66x-12=06(x-2)=0x-2=0X=2 (x-1)^2 + (x-2)^2+(x-3)^2 =0 => 3x^2 -12x +14 = 0 . Now, D = b^2 - 4ac => (-12)^2 - 4×3×14 => 144 - 168 => -24 . Since the discriminant is less than 0 . Therefore, it has zero real root.