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| 1. |
The nth term of Ap is 6n+2.find it\'s common difference |
| Answer» an = 6n + 2{tex}\\Rightarrow{/tex}\xa0a1\xa0= 6\xa0{tex}\\times{/tex} 1 + 2 = 8a2 = 6\xa0{tex}\\times{/tex}\xa02\xa0+ 2 = 14{tex}\\therefore{/tex}\xa0common difference = a2\xa0- a1\xa0= 14 - 8 = 6 | |