1.

The number of bacteria in a certain culture doubles every hour. Ifthere were 30 bacteria present in the culture originally, how many bacteriawill be present at the end of 2nd hour, 4th hour andnth hour?

Answer» The bacteria present in the culture originally, at the end of 1st hour, at the end of 2nd, hour, at the end of 3rd hour and so on, are
30, 60, 120, 240,...
this is a GP with `a=30` and `r=60/30=2`.
Number of bacteria at the end of 2nd hour
`=T_(3)=ar^(2)=(30xx2)^(2)=120`.
Number of bacteria at the end of 4th hour
`=T_(5)=ar^(4)=(30xx2^(4))=480`.
Number of bacteria at the end of nth hour
`=T_(n+1)=ar^((n+1-1))=30xx2^(n)`.


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