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| 1. |
The perimeter of the quadrant of a circle id 25 cm.find its area. |
| Answer» Let r be the radius of the quadrant.We know that, Perimeter of the quadrant\xa0{tex}= \\frac { 25 r } { 7 } \\mathrm { cm }{/tex}Given that,\xa0perimeter of a quadrant\xa0{tex}= 25 cm{/tex}{tex}\\Rightarrow \\frac { 25 r } { 7 } {/tex}{tex}= 25{/tex}{tex}\\Rightarrow r = 7 \\mathrm { cm }{/tex}{tex}\\therefore {/tex}\xa0Area of the quadrant{tex}= \\frac { 1 } { 4 } \\pi r ^ { 2 }{/tex}{tex}= \\left( \\frac { 1 } { 4 } \\times \\frac { 22 } { 7 } \\times 7 \\times 7 \\right) \\mathrm { cm } ^ { 2 }{/tex}{tex}= \\frac { 77 } { 2 } \\mathrm { cm } ^ { 2 }{/tex} | |