The product of consecutive positiv integer is 306.we need to find the

1.	The product of consecutive positiv integer is 306.we need to find the integer.
Answer» Let the consecutive no. be x and (x+1) then,A/q, x(x+1)=306 => x²+x-306 => x²-17x+18x-306 => x(x-17)+18(x-17) => (x-17)(x+18) => x=17 or -18 Let two consecutive numbers are x and (x + 1) A/C to question,product of x and (x + 1) = 306 ⇒x(x + 1) = 306 ⇒x² + x - 306 = 0⇒ x² + 18x - 17x - 306 = 0⇒x(x + 18) - 17(x + 18) = 0⇒(x + 18)(x - 17) = 0⇒ x = 17 and -18Hence, numbers are x = 17 and (x +1) = 18

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