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The product of two consecutive positive integer is divided by 2 |
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Answer» 2 Thankyou Hence any integer is of one of the form 2q, 2q+1. Hence n(n+1) = 2((2q+1)(q+1)), which is even. Hence n(n+1) is always even. Hence the product of two consecutive integers is\xa0always divisible by\xa02. |
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