The product of two consecutive positive integers is 306. We need to fi

1.	The product of two consecutive positive integers is 306. We need to find the integers
Answer» First consecutive positive no is x and another x+1 so product x(x+1)=360 So x square + x+1 whole square =306And factors are +18and -17So x= 17 x+1 = 17+1=18 We have to let the consecutive positive integers be x and x+1So x(x+1)=306 Let two consecutive positive integers =x,x+1Product of two consecutive integers=306X(x+1)=306X square+x-306=0By quadratic formula-b+-√d\\2a-1+-√1-4(1)(-306)/2-1+-√1225/2-1+-35/2X=-1+35/2=34/2=17Or x=-36/2=-18So x=17So two consecutive positive integers=17and17+1=18

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