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The quadratic polynomial, the sum of whose zeroes is -5 and their product is 6 , is(1 Point) |
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Answer» Sum of zeroes = -5Product of zeroes = 6 So, we know that when we have to find the quadratic equation then we use this formulas : x2-(sum of zeroes) x+product Now, x2-(-5)x+6. Required quadratic equation is --> x2+5x+6. Let the quad. polynomial be ax^2+bx+c and whose zeroes are alpha and beeta. According to question- sum of zeroes=-b/a=-5/1 products of zeroes =c/a=6/1 from here, a=1, b=5 and c=6 thus, required quadratic equation is x^2+5x+6 |
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