InterviewSolution
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InterviewSolution
| 1. |
The radius of a circle with centre (-2,3) is 5 units the point (2,5) lies |
| Answer» The point (2,5) lies inside the circle.To check whether a point lies inside or outside the circle, we write the equation of circle and substitute the point in the equation.If the value of the equation is equal to r² then the point lies on the circle.If the value of equation is less than r² then it lies inside the circle.And if the value of the equation is greater than r² then it lies outside the circle.Writing the equation of circle first,(x -h)2 +(x-k)2 = r2 , where (h,k) is the center of circle and r is the radius of the circle.Substituting the values we get,(x -(-2))2 +(x-3)2 = 52Above equation is the equation of the circle.Now we have to find whether the point lies inside or outside the circle, we substitute the point in the equation of circle.(2 -(-2))2 +(5-3)2 = 5216+4 = 20 , which is less than r² = 5² =25.Therefore the point (2,5) lies inside the circle.\xa0 | |