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The rain water from a roof of 44 m x 20 m drains int

Answer» Length of the roof (l) = 44 m,Breadth of the roof (b) = 20 mLet the height of the water on the roof be h m.Volume of water falling on the roof = l{tex}\\times{/tex}b{tex}\\times{/tex}h= 44{tex}\\times{/tex}20{tex}\\times{/tex}h= 880hRadius of the cylindrical vessel\xa0{tex}( R ) = \\frac { 4 } { 2 } = 2 m{/tex}Height of the water in the cylindrical vessel (H) = 3.5 mVolume of the water in the cylindrical vessel =\xa0{tex}\\pi R ^ { 2 } H{/tex}{tex}= \\frac { 22 } { 7 } \\times 2 \\times 2 \\times 3.5{/tex}{tex}= \\frac { 308 } { 7 }{/tex}= 44Volume of water falling on the roof = Volume of the water in the cylindrical vessel{tex}\\Rightarrow{/tex}\xa0880 h = 44{tex}\\Rightarrow h = \\frac { 44 } { 880 }{/tex}{tex}\\Rightarrow h = \\frac { 44 } { 880 } \\times 100{/tex}{tex}\\Rightarrow{/tex}\xa0h = 5 cm{tex}\\Rightarrow{/tex}\xa0Height of the water on the roof is 5 cm.


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