1.

The ratio of the volumes in water an glycerin in 320 cc of a mixture is 1 : 3. The quantity of water (in cc) that should be added to the mixture so that the new ratio of the volumes of water and glycerin becomes 2 : 3 is1). 552). 803). 62.54). 64

Answer»

⇒ Let the WATER added be X cc

⇒ Amount of water in previous MIXTURE = 320 × (1/4) = 80

⇒ After ADDING x cc amount of water will be (80 + x)

⇒ Amount of glycerin = 320 × (3/4) = 240

⇒ New ratio = (80 + x)/240

⇒ (80 + x)/240 = 2/3

⇒ (80 + x) = 160

∴ x = 80


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