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The refractive indices of a prism for red, violet and yellow lights are `1.52, 1.62 and 1.59` recp.What is the dispersive power of the prism ? If mean deviation is `40^(@)`. What is angular dispersion produced by the prism ? |
Answer» Correct Answer - `0.169`; `6.76^(@)` Here, `mu_(r ) = 1.52, mu_(v) = 162` and `mu_(y) = 1.59` Dispersive power `(omega)` `= (mu_(v) - mu_(r ))/(mu_(y) - 1) = (1.62 - 1.52)/(1.59 - 1) = (0.10)/(0.59) = 0.169` Angular dispersion : `delta_(v) - delta_(r ) = omega xx delta` `= 0.169 xx 40^(@) = 6.76^(@)` |
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