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The roots of the equation x^2-3x-m (m+3)=0 where m is a constant

Answer» {tex}x^2 - 3x -m(m + 3) = 0\xa0{/tex}{tex}\\Rightarrow{/tex}{tex}\xa0x^2 + mx - (m + 3)x - m(m + 3) = 0{/tex}{tex}\\Rightarrow{/tex}{tex}x(x+m)-(m+3)(x+m){/tex}{tex}\\Rightarrow{/tex}\xa0(x+m) (x\xa0- m - 3) = 0x = -m and m + 3


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