1.

The roots of the equation x2 +x -p(p+1 ) wherw p is constant

Answer» {tex}x^2 + x - p(p+1) = 0{/tex}{tex}x^2 + (p+1)x - px - p(p+1) = 0{/tex}{tex}x(x+ p + 1) -p(x + p + 1) = 0{/tex}(x + p + 1)(x - p) = 0\xa0x = - p - 1, p


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