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The roots of the quadratic equation 6x² – x – 2 = 0 are\xa0*

Answer» 6x^2 - x - 2 = 06x^2 -4x +3x - 2= 02x(3x-2)+1(3x-2) =0 (3x-2) (2x+1) =03x-2=0,2x+1=03x=2,2x=-1Therefore X=2/3 , x=-1/2
\xa06x² – x – 2 = 0\xa06x² – 4x+ 3x – 2 = 02x(3x - 2) + 1 (3x - 2) = 0(3x -2) ( 2x + 1) = 03x - 2 = 0 and 2x + 1 = 03x = 2 and 2x = -1x = 2/3 and x = -1/2


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