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The side if square is 10 cm.find the area of circumscribed and inscribed circle.

Answer» Side of square = 10cmFor incirclediameter of circle = side of square{tex}\\Rightarrow r = \\frac{{10}}{2} = 5cm{/tex}{tex} \\therefore {/tex}\xa0Area of incircle\xa0{tex}= \\pi {r^2}{/tex}{tex}= 3.14 \\times 5 \\times 5{/tex}78.50 cm2For circumcircleAC will be the diameter because\xa0{tex} \\angle B = 90^\\circ {/tex}Now, In\xa0{tex} \\triangle ABC{/tex}, by pythagoras theoremAC2 = AB2 + BC2{tex}\\Rightarrow {/tex}\xa0AC2 = 102 + 102{tex}\\Rightarrow {/tex}\xa0AC2 = 200{tex}\\Rightarrow AC = \\sqrt {200} = 10\\sqrt 2 cm{/tex}{tex} \\therefore {/tex}\xa0Area of circumcircle\xa0{tex}= \\pi {r^2}{/tex}{tex}= 3.14 \\times {\\left( {5\\sqrt 2 } \\right)^2}{/tex}{tex}= 3.14 \\times 50{/tex}= 157cm2


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