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The speed `v` of a car moving on a straight road changes according to equation, `v^2 = 1 + bx`, where `a and b` are positive constants. Then the magnitude of acceleration in the course of such motion : (x is the distance travelled).A. increasesB. decreasesC. stay constantD. first decreases and then increases |
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Answer» Correct Answer - C `v^2 = a + bx` `v` increase as `x` increases `a = v (dv)/(dx) = (1)/(2) (d)/(dx) (v^2) = (b)/(2)` Hence, acceleration is constant. |
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