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The sum of 2 numbers is 8 . If their sum is 4 times their difference find the number |
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Answer» Let the numbers be X and Y.In first case X + Y = 8In second case X + Y= 4(x-y)After solving the both equation you will get x is equal to 5 and Y is equals to 3 Let number will be x and y.Given, x+y =8.......(i) 4(x-y) =x+y. Or, 4x-4y =8.........(ii) [x+y =8 in eq. i ] Now, multiply by 4 in eq. i Then we get, 4x+4y =32......(i)Now, Substract eq.(ii) from eq.(i)4x+4y =32,4x-4y =8,- + -____________ 8y =24 Or, y =3.Put the value of y in eq.(i)X+y =8x+3 =8X. =8-3 =5.Hence, number will be 5 and 3. Let x+y=8. ____(1eq).4 (y-x)=x+y______2nd(eq)Solve bothEquation X=0 Y=8 Right answer |
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