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The sum of 3 numbers i n Ap is 12 and sum of their cubes is 288.find Ap

Answer» Let Three numbers be a-d ,a ,a+d a-d+a+a+d=123a=12a=4Now ,(a-d)3+a3+(a+d)3=288 Substitute the value of a(4-d)3 +64 +(4+d)3=288Substitute the formula (a +b)3You will get d Then you will get the required A.P


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