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| 1. |
The sum of first 10 terms of an ap is 100 if first term is 10 find its 16 term |
| Answer» S= n/2 [2Xa+(n-1)d]100= 10/2 [2X10+(10-1)d]100= 5 [20+ 9d]20= 20+9d20-20= 9d0= 9d0= d16th term= a+(16-1)d = 10+15X0 = 10+016th term= 10A.P.= 10, 10, 10, .............. | |