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The sum of first 5 multiple of 3 is ………………………..

Answer» Sum of first 5 multiples of 3:Sum of an AP is:\xa0n/2 \u200b× (2a+(n−1)d)a=3,d=3,n=5Then,\xa0Sum =\xa05/2 ×(2×3+(5−1)×(3))=\xa05/2 \u200b×(6+12)= 5/2\xa0×18= 5\xa0×9=\xa045


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