The sum of first n terms of AP is given by An=2n²+3n.Find the sixteen

1.	The sum of first n terms of AP is given by An=2n²+3n.Find the sixteenth term of the AP.
Answer» 65 T16 = a + ( n-1) d = 5 +15×4= 5 +60 = 65 sorry sum nahi term we get 16th term S1= 5 , s2= a1 + a2 = 14 therefore a2 = 14 - 5 = 9 therefore d = a2 - a1 = 4 now a= 5 and d =4 putting the value of 1st term a and common difference d we get sum of 16th term of the ap Plzz explain me How How 65 145 It is 65

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