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The sum of n terms of an AP is (5n²—3n).find the Ap and hence its 10th trem

Answer» S1=5(1)^2-3(1)=2=a1=aS2=5(2)^2-3(2)=14=a1+a2a2=14-2=12d=12-2=10A.P is 2, 12, 22.......a10=2+9(10)=92


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