The sum of square of two consecutive multiples of 7 is 637. Find the m

1.	The sum of square of two consecutive multiples of 7 is 637. Find the multiple.
Answer» (7x) square +(7(x+1)) square= 63749x^2 + 49(x+1)^2 =637Taking 49 common49( x^2 + x^2 +2x +1) = 6372x^2 + 2x +1 = 637 / 49 = 132x^2 + 2x = 13 - 1 = 12x^2 + x = 6x (x + 1) =62 3 6So multiple s are 7x ie 72=14And 21 we have given thatsum of the squares of two consecutive multiples of 7 is 637. we have to findthe numbers are ??solution:-let the number multiple of. 7 = 7x thenconsecutive multiples of 7 = 7(x+1) now according to question(7x)² + {7 (x+1)}² = 637= 49 x² + 49 (x+1)² = 637= 49 x² + 49( x² +1+2x) = 98x² +98 x +49 = 637= 98x² +98x = 637-49 = 588=> x² +x= 6. or = x² + x -6 =0=> x² +3x -2 x -6 = 0=> x(x+3) -2 (x+3) = 0=> x-2 =0. and x+3 = 0=> x= 2 and -3 answerhence (1) if x = 2the number multiple of 7 is 7×2 =14 it\'s consecutive number multiple of 7 is = 7×(2+1) = 7×3 = 21(2) if x =-3the number multiple of 7 is 7×(-3) = -21it\'s consecutive number multiple of 7 is = 7×(-3 +1) = 7× (-2) = -14Thank you??

The sum of square of two consecutive multiples of 7 is 637. Find the multiple.