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The sum of squares of two consecutive odd numbers is 394 . Find the number |
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Answer» x²+(x+2)²=394 => 2x²+4x+4=394 => x²+2x-195 => x²-13x+15x-195 => x(x-१3)+15(x-13) => x=13 or -15 so if x =13 then x + 2 = 15 and if x = -15 then x+ 2= -13 Let two consecutive no be x and x+2 then A/q, x²+(x+2)²=394 => 2x²+4x+4=394 => x²+2x-195 => x²-13x+15x-195 => x(x-१3)+15(x-13) => x=13 or -15 |
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