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The sum of the first nth odd term of an ap |
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Answer» Thanks bhi nahi kaha mehnat bekar kerdi me thanks ke deta ho thanks kunki mene ye padhe bahut accha N^2is right and {tex}s_n ={n\\over2}[{2a+(n-1)d}]{/tex}in case of odd number series{tex}s_n ={n\\over2}[{2(1)+(n-1)1}]{/tex}{tex}s_n ={n\\over2}[{2+n-1}]{/tex}{tex}s_n ={n\\over2}[{n+1}]{/tex}is the required answer, |
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