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| 1. |
the sum of the square of two consecutive natural number is 313 and find the number |
| Answer» Let 1st no. = x2nd consecutive no. =x+1X^2 + ( x+1)^2 =313X^2 +x^2 +2x+1=3132X^2+2x+1-313=02x^2 +2x -312 = 02(x^2 + x -156) =0X^2 +x-156=0Splitting middle termX^2 +13x -12x -156 =0X(x+13)- 12(x+13)=0(x+13)(x-12)=0x+13=0 or x-12=0X= -13 or x=12X= -13(not possible as -13 is not nature number)So, x=12 and x+1 = 13Hope this will help u? | |