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| 1. |
The sum of three numbers in AP is 27 and their product is 405 find the number |
| Answer» Let no. are a-d,a,a+da-d+a+a+d=273a=27a=9(a-d)(a)(a+d)=405(9-d)(9)(9+d)=40581-dsquare=45-dsquare=-36d=6no.area-d=9-6=3a=9a+d=9+6=15 | |