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The sum of two no 15 if sum of their reciprocal is3/10 find the no

Answer» let nos are x and yx+y=15 x = 15 - y1/x + 1/y=3/101/15-y + 1/y=3/10(y+15-y)10 = 3y(15-y)150=45y-3y2y2-15y+50=0y(y-10) - 5(y-10)=0y=10 , 5x=5 , 10\xa0
Sol:Let one of the numbers be x.Other number is (15 - x)Sum of their reciprocals = 3/101/x + 1/(15 - x) = 3/10(15 ) / (15x - x2) = 3/10150 = 45x - 3x23x2 - 45x + 150 = 0x2 - 15x + 50 = 0(x - 10)(x - 5) = 0x = 10 or 5Therefore, the numbers are 10 and 5.If x = 15


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