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The sum of two numbers is 16 and their difference is 18

Answer» 510 = 92 x 5 + 5092 = 50 x 1 + 4250 = 42 x 1 + 842 = 8 x 5 + 28 = 2 x 4 + 0∴ HCF of 510 and 92 = 2Product of two numbers = Product of their LCM and HCF510 x 92 = 2 x LCMLCM = (510 x 92) / 2 = 23460∴ LCM of 510 and 92 = 23460.
X+Y =16------1eq. X-Y=18-----2nd. BY eliminate method X-Y=18 X+Y=16 THEN,-Y AND +Y Is cut After that 2X=16+18THEREFORE , 2X=34 THEN,X= 17 Y= -1
Suppose one number is X,And another be Y.By first condition,X+Y=16………….(1)By second condition,X-Y =18………….(2)Adding both the equation,X+Y=16+X -Y=18…………….2x =34 (y,-y get cancelled)X=17.Substitute x=17 in (1),17+y=16Y=16–17Y= -1(x=17,y=-1).


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