The sum of two numbers is 16and the sum of there reciprical is1/3 find

1.	The sum of two numbers is 16and the sum of there reciprical is1/3 find the numbers
Answer» Thanks yogita ji Nice Yogita ji The numbers are 4 and 12 Let one number be x.therefore , another number = 16 - x (because sum of two numbers is 16)also ,1/x + 1/16 - x = 1/3 (Given)\xa0(16 -x +x) / x(16 -x) = 1/3 16*3 = x(16 - x) 48 = 16x - x²or x² - 16x + 48 = 0or x² - 12x - 4x + 48 =0\xa0x(x-12) -4(x-12) =0x-4 = 0 or x-12 =0x=4 or x=12hence one Number is 4 .and another number = 16 - x =16 - 4 = 12 .

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