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The system of linear equations `x+y-z=6, x+2y-3z=14` and `2x+5y-lambda z=9` has a unique solution (A) `lambda=8` (B) `lambda !=8` (C) `lambda=7` (D) `lambda !=7` |
Answer» For a system of linear equations having unique solution, value of the determinant should not be `0`. Here, `Delta = |[1,1,-1],[1,2,-3],[2,5,-lambda]| != 0` `=>[-2lambda+15-1(-lambda+6)-(5-4)] != 0` `=>-lambda+8 != 0` `=>lambda !=8` So, option `B` is the correct option. |
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