1.

The taxi fare after each km when the fare is Rs15 for the first km and Rs 8 for each additional km

Answer» No, because the total fare (in Rs.) after each km is 15,(15+ 8), (15 + 2 x 8), (15+ 3 x 8),…= 15,23, 31, 39,…Let t1\xa0= 15,t2\xa0= 23,t3\xa0= 31 and t4\xa0= 39Now, t2\xa0- t1\xa0= 23 - 15 = 8t3\xa0- t2\xa0= 31 - 23 = 8t4\xa0- t3\xa0= 39 - 31 = 8Since, all the successive terms of the given list have same difference i.e., common difference = 8Hence, the total fare after each km form an AP.


Discussion

No Comment Found