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The three vertex of a parallelogram are (3,4, (3,8)and (9,8)find the fourth vertex?

Answer» let ABCD is a IIgram with A(3,4) , B(3,8) , C(9,8), D(X,Y)AC and BD are diagonals which bisect each other at mid point O\xa0thus mid point of AC=(3+9)/2, (4+8)/2 = 6, 6mid point of BD = (3+x)/2 , (8+y)/2mid point of AC = mid point of BD6, 6 = (3+x)/2 , (8+y)/2(3+x)/2=6 3+x=12 , x=9(8+y)/2=6 8+y=12 , y = 4the fourth vertex is (9 , 4)check ur answer 3+9/2 = 12/2 , 8+4/2 =12/2 6,6 ok\xa0


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