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The value of `|(a_(1) x_(1) + b_(1) y_(1),a_(1) x_(2) + b_(1) y_(2),a_(1) x_(3) + b_(1) y_(3)),(a_(2) x_(1) +b_(2) y_(1),a_(2) x_(2) + b_(2) y_(2),a_(2) x_(3) + b_(2) y_(3)),(a_(3) x_(1) + b_(3) y_(1),a_(3) x_(2) + b_(3) y_(2),a_(3) x_(3) + b_(3) y_(3))|`, isA. `a_(1) a_(2) a_(3) b_(1) b_(2) b_(3)`B. `x_(1) x_(2) x_(3) y_(1) y_(2) y_(3)`C. 0D. none of these |
Answer» Correct Answer - C We have, `|(a_(1),b_(1),0),(a_(2),b_(2),0),(a_(3),b_(3),0)||(x_(1),y_(1),0),(x_(2),y_(2),0),(x_(3),y^(3),0)| = 0 xx 0 = 0` `rArr |(a_(1) x_(1) + b_(1) y_(1) + 0,a_(1) x_(2) + b_(1) y_(2) + 0,a_(1) x_(3) + b_(1) y_(3) + 0),(a_(2) x_(1) + b_(2) y_(1) + 0,a_(2) x_(2) + b_(2) y_(2) + 0,a_(2) x_(3) + b_(2) y_(3) + 0),(a_(3) x_(1) + b_(3) y_(1) + 0,a_(3) x_(2) + b_(3) y_(2) + 0,a_(3) x_(3) + b_(3) y_(3) + 0)| = 0` [Using row by-row multiplication] `rArr |(a_(1) x_(1) + b_(1) y_(1),a_(1) x_(2) + b_(1) y_(2),a_(1) x_(3) + b_(1) y_(3)),(a_(2) x_(1) + b_(2) y_(1),a_(2) x_(2) + b_(2) y_(2),a_(2) x_(3) + b_(2) y_(3)),(a_(3) x_(1) + b_(3) y_(1),a_(3) x_(2) + b_(3) y_(2),a_(3) x_(3) + b_(3) y_(3))| = 0` |
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