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The value of a and b, if the zeros of x^2+(a+5)x-(b-4) are -5 and 9 will be _________(a) 47, -5(b) -5, 47(c) -9, 49(d) -4, 45This question was posed to me during an interview.The origin of the question is Zeros and Coefficients of Polynomial topic in portion Polynomials of Mathematics – Class 10 |
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Answer» RIGHT choice is (C) -9, 49 Explanation: The ZEROS of the POLYNOMIAL are -5 and 9. Hence, α=-5, β=9 The polynomial is x^2+(a+5)x-(b-4). Sum of zeros or α+β=-5+9 = \(\FRAC {-coefficient \, of \, x}{coefficient \, of \, x^2} = \frac {a+5}{1}\) -4=a+5 a = -9 Product of zeros or αβ = -45 = \(\frac {constant \, term}{coefficient \, of \, x^2} = \frac {-(b-4)}{1}\) -45=-b+4 b=49 |
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